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  1-ACI350-06 &ACI224R-01,2- Design of Reinforced Concrete by Jack C. McCormac_9th Ed-2013-1118129849_ACI 318-11.pdf pages 43 (Example 2.3), 6.10 Control of Flexural Cracksand excel sheets for chapter 6 RCM ACI Builder v by Eng. Hussein Rida Moment of Inertia of Cracked Section Transformed to Concrete eq Equivalent Stiffness , Is =Ic/n axial force, εc = εc fc/Ec = fs/Es ==> F/(Ac Ec) = F/(As Es) ==> thus As Es = Ac Ec ==> As = Ac * Ec/Es = Ac /n and for moment, εc = εc fc/Ec = fs/Es ==> M*y/(Is Es) = M*y/(Ic Ec) == > Is = Ic Ec/Es = Ic/n
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