LAB8 INF | Capacitor | Series And Parallel Circuits

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mediciones de corriente
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  Universidad de la Salle. Rubio Bridget. Duarte David. MEASUREMENT OF DC CURRENT LAB GUIDE 8: MEASUREMENT OF DC CURRENT David Leonardo Duarte Cano, Jellin Bridget Rubio Hernandez.  I. ANWERS TO QUESTIONS    The capacitors consist of two parallel plates separated by an insulator or dielectric material, so its main purpose is electrical energy storage, whereby there are two ways to perform analysis. By direct or alternating current, this course is only suitable for DC analysis in which it must be the  period of the DC source is infinite so the frequency of it will be zero. Now, with this in mind and using equation (1). R  c = ⁄   (1) When zero frequency, the resistance value of the capacitor for DC is infinite ohms, whereby the only circuit element capable of providing an infinite resistance be open circuit between two  points A and B determined.    Referencing laws Kirchhoff's current; the way in which to increase the measuring range of an ammeter is through a resistive parallel circuit, this means that an ammeter connected directly to a current source mark the actual value of said source through resistance internal, however if another resistor is connected in parallel with the resistance ammeter the new value will be the current passing through the resistance of the multimeter but not the total value which gives the source, so if you want to determine the current value from a source that far exceeds the highest rank ammeter must be connected resistors in  parallel line with the ratio between the value of the current source and the maximum range with ammeter throwing a value scale that generates the fountain.    As a voltmeter is impossible to make a current measurement and the internal resistance thereof is too high and the current through it is minimal tending to zero, thus taking into account that the circuits so far worked they are purely resistive, is recommended voltage measurements with the machine | and through Ohm's law and knowledge of electrical resistance determine the value of the electric current needed there. II. METHODOLOGY For this laboratory it has been decided to start by using the formula for implementing the calculation of the resistivity of a conductor cable, which is shown in equation (2).  =     (2) Where ρ is the coefficient of resistivity of material Cable length L and A is the cross sectional area thereof. Now, with laboratory specifications is attached has the data in Table 1. Ω   ρ of Cooper 0,0172 Ωm  Length 1 m Cross sectional area 3,31 mm 2 Table 1.  Calculation of Resistance. Once the above data it is possible to determine the value of cable resistance, which have a value of R = 52 Ω  whereby it is possible to conduct a similar resistive circuit shown in the simulation of figure 1.  Universidad de la Salle. Rubio Bridget. Duarte David. MEASUREMENT OF DC CURRENT Fig.1.  Circuit of Practice.  For which simulated data of Figure 2 were obtained.   however it is not possible to locate only the wire in the circuit, as doing a short circuit with the source will occur, for that reason I am located an R = 1 Ω  for not greatly affect the values of current through the cable. Fig.2.  Simulated data.  With these simulation data and data obtained from Ohm's law it is possible to find the theoretical data with values of R = 0.0051 Ω  and voltage V = 10 V ;  I = 9.95 A  with which it was obtained an E% I = 0.04%  for current and voltage E% V = 0% , once defined the percentage error is necessary to find the value of the power that is able to tolerate copper wire with P = 0,505 W . For the second part of the laboratory decided to take a ceramic 100 nF capacitor for the practice, which is able to tolerate 60 V and is appended to circuit the the first part, as shown in Figure 4. used to determine that a circuit with source DC current flowing through a capacitor will tend to zero and the only way to go is the cable has been used for the first part. This circuit consists of various combinations of circuits in series and in parallel. In order to have a good practice and development is necessary to make the relevant calculations to can see in the fig 4. III. RESULTS AND COMPARISON.  The first part of the laboratory is the parallel connection of a 12 AWG  cable with a resistance of 0.0051 Ω  and measured value of 0.005Ω  as measured value yielding a  percentage error of E%= 1.69%  therefore is considered as a short circuit, whereby the voltage resistance thereof is 0V at a current infinite, however is a limited supply and maximum current is 6.48 A,   however current values obtained thrown in practice do not match with those obtained in the simulation because the source has a current limiting for safety for that reason one percentage E% = 54,01  error is so this is the same current flowing through the cable.  =   ∗  (3) So this is the same current flowing through the cable. By using equation (3)  is achieved determine the power cable is used dissipating yielding a value of P = 0.2441 W. however, considering that the source delivers a total  power of P = 64.8 W , being the power dissipated by the cable one 0.3777%  of the total, a relatively low value. For the second part of the laboratory, a capacitor with a maximum capacity of 100V  and value of capacitance of 100 nF  in a parallel circuit so it is important to note that a source of DC has an infinite frequency and a period of zero was connected, this means that the capacitor acts as an open circuit or an equivalent resistance of infinite value. Which causes the current in this is zero amperes, while the voltage always tends to be the same source that would 60V . Not only to be in parallel with the source, but Fig 4.  Circuit elected for the practice  Universidad de la Salle. Rubio Bridget. Duarte David. MEASUREMENT OF DC CURRENT  because it acts as the potential difference between two  parallel plates. IV. CONCLUSIONS    The electrical resistance of a conductor cable is directly proportional to the length of the same relationship as between shorter has the resistance decreases, whereas if the cross sectional area decreases the resistance of the cable increases.      As flow through a tube, the flow of electrical current experience increased opposition to his step less oxygen flow may happen, however it must be remembered that if the maximum capacity (power) cable is exceeded this it will  burn and lose its resistive properties.      In a DC circuit capacitor it behaves like an infinite resistance value so the flow of electrical current is zero and seek other ways to go.  III. BIBLIOGRAPHY [1] A. Orozco Naranjo. (2012, Sept). Circuitos Mixtos Resistivos. [Online]. Avaible: http://www.buenastareas.com/ensayos/Medici%C3%B3n-De-Corriente-y-Voltaje-En/5956046.html [2] Leyes de corriente y voltaje de Kirchhoff [Online]. Available: http://www.sapiensman.com/electrotecnia/problemas11.htm.
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